Charge 1 is 8nC and is located at x=-1m. Charge 2 is 12nC and is located at x=3m. Find x where e field is equal to 0 due to the 2 charges.
The Attempt at a Solution
The answer is x=1.8, but I just can't seem to get anywhere near that. I know that x has to be between -1m and 3m b/c the E-field due to the 2 charges can only cancel out when x is in between.
E1=e field due to charge 1
E2=e field due to charge 2
0=E1-E2 <<<it's minus because E2 is acting in the negative directive
0=kq1/(x+1)^2 - kq2/(3-x)^2
0=8/(x+1)^2 - 12/(3-x)^2 <<canceled out k and 10^-9 from the nano.
8/(x+1)^2 = 12/(3-x)^2 << the answer is 1.8, I don't want to write out the rest so just plug 1.8 in. When you plug it in it doesn't equal each other.
From that my answer isn't even close to 1.8m. I think I messed up somewhere in the denominator of the equation above, but I can't see how.