Find x: Solving a Spring Stretch Problem

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    Spring Stretch
AI Thread Summary
The discussion revolves around calculating the distance a spring stretches when a block is kicked with a horizontal velocity. The user initially calculated the angular velocity and centripetal force but struggled to relate these to the spring's stretch. It was clarified that the centripetal force acting on the block is equal to the elastic force of the stretched spring. Additionally, the user was reminded to consider the angular frequency for a stretched spring, indicating that the radius must exceed the spring's natural length. Understanding these relationships is crucial for solving the problem accurately.
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Homework Statement


A relaxed spring is sitting on a horizontal surface. A block attached at one of its ends is kicked, with a horizontal velocity, v1, given to it. The block will move and stretch. Find the distance, x, the spring will stretch. See figure. Find x in meters.

http://i.imgur.com/tYyl3t4.png

Homework Equations


F=-kx

The Attempt at a Solution


I used the equation ω=v/r to find the angular velocity = 1 rad/sec. I then thought that the angular velocity produces a centripetal force, which is the driving force for the spring to stretch. This centripetal force can be found using a=(ω^2)*r which = 1 m/s^2. I however, do not know how to use this force to find how far a spring would stretch when said force is applied. Any help is appreciated!
 
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You forgot the figure?
 
Fixed it, there's a link in the OP.
 
That angular speed is for un-stretched spring, right?
The centripetal force is the elastic force of the spring. And this happens when the spring is stretched. So you have to write the angular frequency for stretched spring (r>lo).
 
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