Find y'' by implicit differentiation

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Homework Help Overview

The discussion revolves around finding the second derivative, y'', through implicit differentiation of a given equation. The subject area is calculus, specifically focusing on derivatives and implicit functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the process of differentiating an equation implicitly to find y'. Some express confusion about their results when attempting to derive y''. There are suggestions to apply the product rule and quotient rule in their differentiation attempts.

Discussion Status

Several participants provide guidance on how to proceed with the differentiation process, including rewriting equations for clarity. There is an exploration of different interpretations of the steps involved, but no explicit consensus on the final form of y'' has been reached.

Contextual Notes

Participants note potential errors in earlier steps and question the assumptions made in the differentiation process. There is an acknowledgment of discrepancies between participants' results and those found in the textbook.

bobraymund
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Homework Statement



Find y'' by implicit differentiation.

Homework Equations



_LARGE_9x2y29.gif


The Attempt at a Solution



_LARGE__fracddx9x2y2_fracddx9.gif


_LARGE_18x2y_fracddx0.gif


_LARGE_2y_fracddx-18x.gif


_LARGE__fracddx_frac-18x2y.gif


_LARGE__fracddx_frac-9xy.gif


I get to this point in the problem, which is I solved for y'. But then when I attempt to take y'', in other words take the derivative of my answer for y', I don't get the answer that is in the back of the book.

Many thanks in advance,
Bob
 

Attachments

  • _LARGE_9x2y29.gif
    _LARGE_9x2y29.gif
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You went astray in the 2nd line and all following lines. The second line should be
18x + 2y dy/dx = 0 and your last line should be dy/dx = -9x/y. Now take the derivative again, keeping in mind that you need to use the quotient rule and the chain rule, in that order.
 
so y*y'=-9x

so take d/dx of both sides

for d/dx(y*y') use the product rule .
 
Bob, your last equation can be rewritten as; y'=-9xy^-1---->from here here you may get the y" by product rule and arrive at having y"=9/y^2(x-y)--->is this what you got in your book?
 
You can rewrite your last equation to: yy'=-9x---> from here try implicit differentiation.
You'll arrive at having: yy"+y'y'=-9; next, substitute the value of y'=-9x/y (previously derived); You'll arrive at having: y"=-9/y^3(9x^2+y^2).
 

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