Finding 2 2x2 matrices resulting in -1

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Homework Help Overview

The discussion revolves around finding two distinct 2x2 matrices such that the product of a matrix and its transpose equals the identity matrix, with a specific reference to the mathematical axiom where i^2 = -1.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the structure of a 2x2 matrix and its transpose, questioning the implications of the identity matrix versus the axiom involving i.

Discussion Status

There is an ongoing clarification regarding the definition of "I" in the context of the problem, with some participants expressing confusion over the terminology used. Guidance has been offered to consider the matrix structure and its properties.

Contextual Notes

Participants are navigating the distinction between the identity matrix and the mathematical concept of i^2 = -1, which has led to some misunderstandings about the problem's requirements.

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Homework Statement


Find two different 2×2 matrices (other than ±I) such that A.AT = I.

Definition: I is referring to i^2=-1 axion
AT=Transpose of A


Homework Equations





The Attempt at a Solution


Trying to make matrices on paper so that A times the transpose of A gives me -1 in all rows and columns.
 
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Have you tried just writing out a matrix A with enries a,b,c,d, what would A^T look like then? Then multiply it out and set equal to I?

I'm not sure what you mean by "I is referring to i^2 = -1". I thought by "I" you meant the identity matrix?
 
No, there's an axion in mathematics apparently where the variable "i squared" (i^2) equals -1. The reason I wrote a Capital I is because I'm working with a program called Maple. It's the same thing, but in the two matrices that I have to find, I can't use the -1 axion.

DanceLink said:
Find two different 2×2 matrices (other than ±I) such that A.AT = I.

Sorry for the confusion.
 
Yes but i^2 = -1 is an imaginary/complex number. You are working with matrices where I refers to the identity matrix.
 
...well I feel stupid as all...

lol thanks for clearing that up. ^^;
 
NoMoreExams said:
Yes but i^2 = -1 is an imaginary/complex number. You are working with matrices where I refers to the identity matrix.

No, i^2 is not imaginary. i is, though:biggrin:
 
Mark44 said:
No, i^2 is not imaginary. i is, though:biggrin:

Haha, yes.
 

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