Finding a basis for null(T) and range(T)

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The discussion focuses on finding the bases and dimensions for the null space and range of the linear transformation T from P3(R) to P2(R). The range is identified as the set of polynomials of the form a1 + a2z + a3z^2, leading to a dimension of 3 with a basis of {1, z, z^2}. The null space is suggested to have a dimension of 1, derived from the rank-nullity theorem, since P3 has a dimension of 4 and the range has dimension 3. The basis for null(T) is unclear, with participants discussing the condition a1 + a2z + a3z^2 = 0 as a potential starting point. The conversation emphasizes the need for clarity on how to handle polynomials in this context.
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Homework Statement


Let Y:P3(R) onto P2(R) is defined by T(a0+a1z+a2z2+a3z3)=a1+a2z+a3z2. Find bases for null (T) and range (T). What are their dimensions?


Homework Equations





The Attempt at a Solution


Well, I am assuming the range is the a1+a2z+a3z^2, so it has dimension of 3, and basis (1, z, z^2). As for the null (T) I'm guessing it has dimension 1, since P^3 has dim = 4, and range (T) has dim 3, so 4-3 = 1.
As for the basis of null(T) I'm not sure. I'm guessing it is when a1+a2z+a3z^2 = 0. But I'm not sure how you would solve it or really how you figure these out when they are polynomials and not vectors or matrices. Thanks.
 
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tehme1 said:

Homework Statement


Let Y:P3(R) onto P2(R) is defined by T(a0+a1z+a2z2+a3z3)=a1+a2z2+a3z2. Find bases for null (T) and range (T). What are their dimensions?


Homework Equations





The Attempt at a Solution


Well, I am assuming the range is the a1+a2z+a3z^2, so it has dimension of 3
According to what you wrote, the range is two-dimensional. Was this a typo?
a1+a2z2+a3z2
Every degree-three polynomial gets mapped to a polynomial that consists of a constant + a squared term. There are no terms in x or in x3 in the range.
tehme1 said:
, and basis (1, z, z^2). As for the null (T) I'm guessing it has dimension 1, since P^3 has dim = 4, and range (T) has dim 3, so 4-3 = 1.
As for the basis of null(T) I'm not sure. I'm guessing it is when a1+a2z+a3z^2 = 0. But I'm not sure how you would solve it or really how you figure these out when they are polynomials and not vectors or matrices. Thanks.
 
yes, it was typo. I made an edit so now the question is as it should be. Thanks
 
tehme1 said:
Well, I am assuming the range is the a1+a2z+a3z^2, so it has dimension of 3, and basis (1, z, z^2). As for the null (T) I'm guessing it has dimension 1, since P^3 has dim = 4, and range (T) has dim 3, so 4-3 = 1.
As for the basis of null(T) I'm not sure. I'm guessing it is when a1+a2z+a3z^2 = 0. But I'm not sure how you would solve it or really how you figure these out when they are polynomials and not vectors or matrices. Thanks.
Start by finding out what T does to the individual functions in a basis for the domain function space.
T(1) = ?
T(x) = ?
T(x2) = ?
T(x3) = ?

That might give you some understanding of what exactly gets mapped to 0 in the range.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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