Finding a basis for null(T) and range(T)

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Homework Help Overview

The problem involves a linear transformation T defined from the space of cubic polynomials P3(R) to the space of quadratic polynomials P2(R). Participants are tasked with finding bases for the null space and range of T, as well as determining their dimensions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants discuss the assumed range of T and its dimension, with one noting a potential typo in the transformation's definition. There is uncertainty about how to derive the basis for the null space and the implications of polynomial mappings compared to vector spaces.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the transformation and its effects. Some guidance has been offered regarding evaluating T on basis functions, which may help clarify the mapping and the determination of the null space.

Contextual Notes

There is a noted discrepancy in the transformation's definition, which has been corrected in a subsequent post. Participants are also grappling with the conceptual differences between polynomial spaces and traditional vector spaces.

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Homework Statement


Let Y:P3(R) onto P2(R) is defined by T(a0+a1z+a2z2+a3z3)=a1+a2z+a3z2. Find bases for null (T) and range (T). What are their dimensions?


Homework Equations





The Attempt at a Solution


Well, I am assuming the range is the a1+a2z+a3z^2, so it has dimension of 3, and basis (1, z, z^2). As for the null (T) I'm guessing it has dimension 1, since P^3 has dim = 4, and range (T) has dim 3, so 4-3 = 1.
As for the basis of null(T) I'm not sure. I'm guessing it is when a1+a2z+a3z^2 = 0. But I'm not sure how you would solve it or really how you figure these out when they are polynomials and not vectors or matrices. Thanks.
 
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tehme1 said:

Homework Statement


Let Y:P3(R) onto P2(R) is defined by T(a0+a1z+a2z2+a3z3)=a1+a2z2+a3z2. Find bases for null (T) and range (T). What are their dimensions?


Homework Equations





The Attempt at a Solution


Well, I am assuming the range is the a1+a2z+a3z^2, so it has dimension of 3
According to what you wrote, the range is two-dimensional. Was this a typo?
a1+a2z2+a3z2
Every degree-three polynomial gets mapped to a polynomial that consists of a constant + a squared term. There are no terms in x or in x3 in the range.
tehme1 said:
, and basis (1, z, z^2). As for the null (T) I'm guessing it has dimension 1, since P^3 has dim = 4, and range (T) has dim 3, so 4-3 = 1.
As for the basis of null(T) I'm not sure. I'm guessing it is when a1+a2z+a3z^2 = 0. But I'm not sure how you would solve it or really how you figure these out when they are polynomials and not vectors or matrices. Thanks.
 
yes, it was typo. I made an edit so now the question is as it should be. Thanks
 
tehme1 said:
Well, I am assuming the range is the a1+a2z+a3z^2, so it has dimension of 3, and basis (1, z, z^2). As for the null (T) I'm guessing it has dimension 1, since P^3 has dim = 4, and range (T) has dim 3, so 4-3 = 1.
As for the basis of null(T) I'm not sure. I'm guessing it is when a1+a2z+a3z^2 = 0. But I'm not sure how you would solve it or really how you figure these out when they are polynomials and not vectors or matrices. Thanks.
Start by finding out what T does to the individual functions in a basis for the domain function space.
T(1) = ?
T(x) = ?
T(x2) = ?
T(x3) = ?

That might give you some understanding of what exactly gets mapped to 0 in the range.
 

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