Finding a Basis for the Orthogonal Complement of W

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To find a basis for the orthogonal complement of the subspace W spanned by vectors v1 = [2,1,-2] and v2 = [4,0,1], the cross product of these two vectors can be directly used, as it yields a vector that is orthogonal to both. The discussion highlights confusion around row reduction and the necessity of finding an orthogonal basis, but it clarifies that the cross product is sufficient. The participants emphasize that v1 and v2 are linearly independent, which supports the use of the cross product. Ultimately, the solution can be simplified by recognizing that the cross product provides the required orthogonal vector without additional row reduction steps. Understanding this method is crucial for efficiently solving similar problems in linear algebra.
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Homework Statement



Let W be the subspace of R^3 spanned by the vectors
v1=[2,1,-2] and v2=[4,0,1]
Find a basis for the orthogonal complement of W

Homework Equations



None

The Attempt at a Solution



I can do this question except for the fact when i get the matrix in form

[2,1,-2/0
4,0,1/0]

i get to this bit but saying the complement is equal to (col(A))=null(A^T)

i can't perform reduced matrix stuff when there is not an odd number at the front i just can't do it can someone start of the next step for me? if so i can do the rest of the question

it is a resit i have tomorrow and we were told today that this question is in it, so it is worth a lot for me to know it by then
 
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for example if someone could show me even how to reduce

[4,3
2,1]
i would be fine

i just don't understand how it is done
 
ooo i might have it i just read that i can interchange rows if so i am fine as i can let it become

1,-2,2/0
0,1,4/0

which i can easily reduce :D

grrr rows not columns
 
You don't even have to perform row reduction. It is apparent by inspection that v1 and v2 are linearly independent (one is not a multiple of the other). So what you need to do is to find an orthogonal basis for W using a well known algorithm, and use a vector operation to find the vector orthogonal to both of them.
 
ok i am very confused now i have the basis

span{0,4,1}

is that right i managed to reduce it i think to
1 0 0/0
0 1 -4/0
 
Defennder said:
You don't even have to perform row reduction. It is apparent by inspection that v1 and v2 are linearly independent (one is not a multiple of the other). So what you need to do is to find an orthogonal basis for W using a well known algorithm, and use a vector operation to find the vector orthogonal to both of them.

well now i am worse for wear, how would i do that? i thought the only way to find the complement to W is to use row reduction
 
The cross product of two vectors is perpendicular to both and so spans the subspace (in R3) orthogonal to the subspace spanned by the two vectors.
 
Oh wait, you don't even need to find an orthogonal basis for W. The cross product would do. Silly me.
 

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