Finding a dimensionless time in a very basic problem

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The discussion centers on determining the dimension of the reaction constant k in the chemical reaction C + C --> Product, where the rate is defined as r=kc². The user successfully derives that k has dimensions of V/MT but struggles with finding a dimensionless time variable. They propose τ=t/(1/c₀k) but find discrepancies when comparing it to the solution manual's τ=t/(V/Q), questioning the manual's accuracy. The conversation highlights the need for consistent units across both sides of the equation, particularly regarding the inflow rate, which should be clarified as a volume inflow rate. The problem emphasizes the importance of dimensional analysis in chemical kinetics.
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Homework Statement



In the chemical reaction problem, assume that the reaction is C + C --> Product, and the chemical reaction rate is r=kc^{2}, where k is the reaction constant. What is the dimension of k? Define dimensionless variables and reformulate the problem in dimensionless form. Solve the dimensionless problem to determine the concentration.

Homework Equations


We are assuming temperature is not relevant.

The mathematical model given by the initial value of the problem is as follows.

\frac{dc}{dt} = \frac{q}{V}(c_{i}-c)-k^{2}c , t>0

In this problem, c is the concentration, t is time, q is the inflow rate (mass/time), V is the volume, and k is the reaction constant.


The Attempt at a Solution



First, I equalized the dimensions on both sides to get that k=\frac{V}{MT} . This part seems simple as the dimensions work now.

However, I am being asked to dimensionalize the problem. Finding a dimensionless concentration is easy, C=\frac{c}{c_{i}}. I am trying to find a dimensionless time. I have gotten as far as \tau=\LARGE{\frac{t}{\frac{1}{c_{0}k}}}, since c_{0} * k has units of c_{0}=\frac{M}{V}, and k=\frac{V}{MT} This much is easy. However I look in the solution manual. It is telling me that the dimensionless time \tau=\LARGE{\frac{t}{\frac{V}{Q}}}. When I work out the units, I get t on the top, but the bottom is \LARGE{\frac{V}{Q}=\frac{V}{\frac{M}{T}}=T\frac{M}{V}}. But \frac{M}{V} is not dimensionless, so \tau=\frac{M}{V}. Can anyone figure this out? Seems beyond obvious and ridiculously simple of a problem, is my solution manual blatantly wrong or am I just completely clueless?
Thank you!
 
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tomgill said:
\frac{dc}{dt} = \frac{q}{V}(c_{i}-c)-k^{2}c , t>0

In this problem, c is the concentration, t is time, q is the inflow rate (mass/time), V is the volume, and k is the reaction constant.

Unless you left out some constants, the units don't match up. LHS has units of c/time so to match it, q has to be "volume inflow rate" or something like that, with units volume/time.
 
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