Finding a Linear Transformation with specific domail and range

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SUMMARY

The discussion focuses on determining a matrix representation of a linear transformation L in MATLAB, specifically requiring that the matrix has two null columns. The transformation is defined by L(1)=(2 -1)', L(1-x)=(1 0)', L(1+x^2)=(1 1)', and L(1+x^3)=(1 2)'. The user initially constructed a matrix A=[2 1 1 1; -1 0 1 2] and a transformation matrix P but found that it did not meet the criteria of having two null columns. The solution involves finding a different basis for the domain that results in the desired matrix characteristics.

PREREQUISITES
  • Understanding of linear transformations and their matrix representations
  • Familiarity with MATLAB for matrix operations
  • Knowledge of kernel (null space) concepts in linear algebra
  • Ability to construct and manipulate basis vectors for vector spaces
NEXT STEPS
  • Explore how to find the kernel of a matrix in MATLAB
  • Learn about changing bases in linear algebra and its impact on matrix representation
  • Study the properties of linear transformations and their matrix forms
  • Investigate the implications of null columns in matrix representations of linear transformations
USEFUL FOR

Students in linear algebra, MATLAB users working with linear transformations, and anyone interested in understanding matrix representations with specific properties.

apdixon
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Hey, i have an assignment in MATLAB class which is
Let L be a linear transformation such that
L(1)=(2 -1)'
L(1-x)=(1 0)'
L(1+x^2)=(1 1)'
L(1+x^3)=(1 2)'
Determine a matrix in domain such that with the canonical in range, the matrix that represents L has two null columns.

I don't know exactly what they're asking me to find. I found L by solving LP=A, being A the transformed matrix [2 1 1 1;-1 0 1 2], and P the matrix P=[1 1 1 1;0 -1 0 0;0 0 1 0;0 0 0 1]. But it doesn't have two null columns, and it was too easy to find to be true. Pleaaaase help!
 
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You found the matrix for L where the basis for the domain is {1, x, x2, x3} (which is reflected in how you constructed P). If you use a different basis for the domain, you'll get a different matrix that represents the linear transformation L. The problem is asking you to find a basis for the domain so that the matrix has two null columns.
 
Thank you! I found the Ker for A=[2 1 1 1; -1 0 1 2], then constructed a matrix F with the Ker in the first two columns and (0100)' and (1000)' in the next two so that i had a matrix of 4x4 and then multiplied A*F. I found L=
0 0 1 2
0 0 0 -1 .
 

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