Hey guys Im having a little bit of trouble with using and understanding the linear factorization theorem to find the polynomial function. 1. The problem statement, all variables and given/known data Find an nth degree polynomial function with real coefficents satisfying the given conditions. n=3; -5 and 4+3i are zeros; f(2)=91 2. Relevant equations 3. The attempt at a solution 1) Since the polynomial has a degree of 3 I know there must be 3 linear factors which are: (x+5) because -5 is a real zero and (x-4+3i) but also its conjugate (x-4-3i) are the complex zeros. 2) Now I multiply the 3 linear factors (x-4+3i)(x-4-3i)= x2-4x-3xi-4x+16+12i+3ix-12i-3i2 and when I combine like term I get: x2-8x+19 which I multiply by the remaining linear factor (x+5): x3-3x2-21x+95 To find the function I apply f(2)=91 f(2)=an(23-3(2)2-21(2)+95)=91 so 8-12-42+95=49an=91 I isolate the variable by dividing its coefficient and get: an=91/49 simplified to 13/7 Now I substitute 13/7 for an and multiply by the product of the linear factors to get find the polynomial function: f(x)=13/7(x3-3x2-21x+95) and end up with a messy looking product...anyway the real answer is: f(x)=x3-3x2-15x+125 I have checked and double checked this problem several times to look for arithmetic mistakes but I just cant seem to match the right answer. I dont know if I just dont understand the concept (honestly I have a shaky understanding of zeros of polynomials in the first place, Im just learning about them today) or if Im just being sloppy with my arithmetic. Any help would be appreciated. Thank you.