- #1
The Head
- 144
- 2
- Homework Statement
- Find when the system of equations is unique:
x-y-2z-2w= 3
y+z+w= 4a+3
z+3w= -4a-4
(-a+2)w= b+4a^2-4a-7
- Relevant Equations
- Full Rank = Unique
It makes sense that a=2 would cause problems because then we wouldn't have a matrix of full rank and we'd be unable to determine a value for w. But the key also says that when b+4a^2-4a-7≠0. Why is that an issue? For example, if a=1, that just says implies that w=0. Through back-subsitution, we get z=-8, y=15, x=2. And the solution: (2, 15,-8, 0) is unique still because it's the only possible solution, right?
What am I missing here?
What am I missing here?