Finding a Vector Equation for a Plane with Scalar Equation 2x-y+3z-24=0

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The discussion focuses on deriving a vector equation for the plane defined by the scalar equation 2x - y + 3z - 24 = 0. The solution involves rearranging the scalar equation to express y in terms of x and z, resulting in y = 2x + 3z - 24. By substituting parameters s and t for x and z respectively, the vector equation is formulated as r(s, t) = si + (2s + 3t - 24)j + tk, which accurately represents the plane in vector form.

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thomasrules
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Find a vector equation for the plane with scalar equation

2x-y+3z-24=0

I have tried but I have no idea at all really how to do it...I have to do it using geometry just to let you know
 
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Solve for y: y= 2x+ 3z-24. Now use x and z as parameters: you can call them s and t if you like:

x= s, y= 2s+ 3t- 24, z= t

Then r(s, t)= si+ (2s+ 3t- 24)j+ tk.

Is that what you mean?
 

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