Finding acceleartion components

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The discussion focuses on calculating the acceleration components of a proton subjected to a constant force while moving at a relativistic speed of 0.9c. The force applied is given as F=(-3.00 X 10^-12)i + (5.00 X 10^-12)j. The correct formula for acceleration is derived from F= (ma)/(1-(v^2/c^2))^3/2, with the clarification that the denominator should be the square root of (1-v^2/c^2). Additionally, the angle between the force and acceleration vectors can be determined using the dot product method.

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ultrabionic_ang
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So the problem goes:

A proton, with rest mass 1.67x10^-27 kg, is moving at v=.9c (where c= speed of light) in the positive x direction, relative to the reference frame of a physics laboratory. Then, a constant force F=(-3.00 X 10^-12)i + (5.00 X 10^-12)j is applied to proton

a) find x and y comps of accl of proton after F was just applied

Bassically, i just used this equation to solve for x and y comps of accl:

F= (ma)/(1-(v^2/c^2))^3/2 and solved for a, and plugged in x and y comps..

is that right?

b) find the angle between F and the acceleration that was calculated in part a...

not sure how to go about that.. is the dot product of F and a taken in order to find the angle?

thanks!
 
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youve got the right idea for a)...except its the square root of (1-v^2/c^2)...so^1/2

and for b)..im supposing you have to find the force vector components..and then, you know
 

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