Finding all values that satisfy the equation

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Homework Help Overview

The discussion revolves around finding all values of x in the interval [0, 2pi] that satisfy the equation tan^2(x) - 1 = (2/sqrt3)tan(x). The subject area includes trigonometric equations and their solutions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the possibility of solving the equation without the quadratic formula and question whether it would yield exact answers. There is also mention of using trigonometric substitutions and the implications of the quadratic formula when expressed in terms of tan(x).

Discussion Status

Some participants have provided guidance on using the quadratic formula and have clarified how to find all solutions within the specified interval. There is acknowledgment of the need to consider general solutions for the tangent function, and some participants express understanding of the concepts discussed.

Contextual Notes

Participants note that finding exact answers may depend on the interval considered, and there is a distinction made between the general solutions for tangent compared to sine and cosine functions.

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Homework Statement


Find all values of x in the interval [0,2pi] that satisfy:

tan^2(x)-1=(2/sqrt3)tan(x)


Homework Equations


Quadratic formula


The Attempt at a Solution


Is there anyway to this without using the quadratic formula that will get me exact answers?
Also will using the quadratic formula give me exact answers?
 
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Not that I know of, but if there is (there most likely is) then it would involve trig substitutions and such and would involve much more work and complications than just using the quadratic formula.

Yes, of course it will! Do you trust the quadratic formula when the quadratic is in terms of x? Well then it works for quadratics in terms of u where u=f(x), in this case, u=tan(x).
 
i think the quadratic formula would be the easiest...
And the exact answers as you say can be found only for a particular interval [-pi/2,pi/2]...or else you get a general solution...
 
Yup thanks for the reply, I ended up doing using the quadratic formula and ended up simplifying nicely (i got tanx= -sqrt3/3, sqrt3)

but one question how would i find ALL the values on [o,2pi], i know how to find the ones in the first quadrant (i.e. tanx= sqrt3 => x=pi/3 ) but how do i find the rest? I forget how to do that.
 
you know general soln of tan(x)=y is
x = tan-1(y) + k*pi , where k can be any integer.
just substitute different values of k and get your answer...
 
Ok is it the same thing for sin and cos? thanks in advance.
 
did you understand it?
 
Yup that cleared A LOT of things up. Thanks a mill.
 

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