Finding Amplitude-simple harmonic motion

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Homework Help Overview

The discussion revolves around a simple harmonic motion problem related to the number of daylight hours in a day, specifically modeling the variation in daylight hours throughout the year using a sine function. The original poster is attempting to determine the amplitude based on given minimum and maximum daylight hours.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of amplitude as half the difference between the maximum and minimum daylight hours. The original poster expresses confusion over the correct value and mentions multiple attempts to submit answers.

Discussion Status

Some participants have provided guidance on how to find the amplitude, while the original poster continues to face issues with the submission of their answer. There is an ongoing exploration of potential misunderstandings or errors in the calculations.

Contextual Notes

The original poster has indicated a deadline for the assignment and mentioned a similar problem with different values, suggesting a broader context of homework constraints. There is uncertainty regarding the correctness of the webwork platform's feedback on their submissions.

Cheer4WVU
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Homework Statement


Simple harmonic motion problem.
The number of daylight hours in a day is harmonic. Suppose that in a particular location, the shortest day of the year has 6.5 hours of daylight and the longest day of the year has 17.5 hours. Then, we can model its motion with the function N=Asin(bt)+C where t is expressed in days and A, B > 0. Find A and B, using 365 days for one year


Homework Equations


N=Asin(bt)+C


The Attempt at a Solution



I found B to be .017214
I found C to be 12
I have no clue how to find the amplitude.. I've tried a million different ways.. submitted the answers.. and it keeps telling me its wrong.. so if anyone can help.. pllleeaassee do.. its due at midnight tonight and I have another problem exactly like this but with two different numbers in replace of the 6.5 and 17.5.
How do you find amp??
 
Last edited:
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If the minimum is 6.5 and the maximum is 17.5, then what is the difference between these?

That is your peak-to-peak amplitude.

Your amplitude is simply half of this.
 
I tried 12 and it's still wrong.. For the phase shift I put 12.. and that was right.. I don't know what to do?
 
Where did you get 12 from?

Have you sketched the graph?

The amplitude is half of the difference between your max and min.
 
17.5+6.5=24
24/2=12

I'm not very good at this stuff.. so I really don't know how to draw the graph.. i know how a sin wave goes.. but I'm just confused. I don't want you to do it for me.. i just want to know how to find amplitude.. but I'm confused because i understand what you are saying about the amplitude being half the difference between the max and min.. but it keeps telling me when i submit the answer that its wrong.
 
Cheer4WVU said:
i understand what you are saying about the amplitude being half the difference between the max and min.. but it keeps telling me when i submit the answer that its wrong.


Did you submit 6 hrs ?
 
yes.. still wrong
 
I'm sorry, (17.5 - 6.5)/2 = 5.5 Is it still wrong?
 
yes.. i don't know if there is something wrong with the webwork or what.. i tried doing the same thing you suggested with the other numbers on the other problem i was given to do.. and it didnt work either..
 

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