Finding an angle given only the Coefficient of static friction

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Homework Help Overview

The problem involves determining the angle at which a box begins to slide down a board, given only the coefficient of static friction (0.22) between the box and the board. The context is rooted in the principles of static friction and forces acting on an object on an inclined surface.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the box, including gravity and static friction, and question how to find the angle with limited information. There is a focus on understanding the relationship between the coefficient of static friction and the forces involved.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some hints have been provided regarding the analysis of force components, but there is no consensus on how to proceed with the calculation of the angle.

Contextual Notes

Participants note the lack of information about the weight of the box and express confusion about how to set up a formula with only the coefficient of static friction provided.

slu1986
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1. A box sits on a horizontal wooden board. The coefficient of static friction between the box and the board is 0.22. You grab one end of the board and lift it up, keeping the other end of the board on the ground. What is the angle between the board and the horizontal direction when the box begins to slide down the board


2. Homework Equations
µ = f / N



3. I do not understand how to calculate an angle when only one variable is given. I know how to calculate the angle when you're able to calculate the sides and then use the arc tan to solve for the angle. If someone could please explain how to work out this problem I would greatly appreciate it.
 
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Hint: What forces act on the box just before it begins to slip? What must the net force be at that point? Analyze the vertical and horizontal force components.
 
The forces that act on it are gravity 9.8 m/s^2 and static friction. The net force's must sum up to zero, but I still don't understand how to find an angle when only the coefficient of static friction is the only variable given.
 
slu1986 said:
The forces that act on it are gravity 9.8 m/s^2 and static friction. The net force's must sum up to zero, but I still don't understand how to find an angle when only the coefficient of static friction is the only variable given.
Don't forget the normal force.

Hint: Consider force components parallel to the board's surface.
 
The normal force would be the weight of the box right? But that information is not given in the problem. Only one variable is given. This is very puzzling to me b/c I don't understand how to attempt setting up a formula to solve for the angle when only 0.22 is given.
 
slu1986 said:
The normal force would be the weight of the box right?
No, it depends on the angle.
But that information is not given in the problem. Only one variable is given.
Call the mass of the box "m". You won't need it.
This is very puzzling to me b/c I don't understand how to attempt setting up a formula to solve for the angle when only 0.22 is given.
Please tell me (symbolically, not with numbers):
-the normal force
-the static friction
-the component of the weight parallel to the board

Then write an equation for force components parallel to the board's surface.
 

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