Finding an electric field from a radio station

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SUMMARY

The discussion focuses on calculating the electric field generated by a radio station transmitting at 500 kW from a distance of 25 km. The energy emitted over a time interval is expressed as Pdt, where P equals 500 kW. The energy density of the electromagnetic wave is defined as w = (1/2)ε₀E², allowing for the derivation of the electric field amplitude E using the relationship P dt = w·dV, where dV is the volume of the spherical shell at the specified distance.

PREREQUISITES
  • Understanding of electromagnetic wave principles
  • Familiarity with the concept of energy density in physics
  • Knowledge of spherical coordinates and volume calculations
  • Basic grasp of radio frequency transmission and power measurements
NEXT STEPS
  • Study the relationship between power and electric field in electromagnetic waves
  • Learn about the derivation of energy density in electromagnetic fields
  • Explore the implications of distance on electric field strength
  • Investigate the effects of different transmission powers on electric field calculations
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Physics students, electrical engineers, and professionals involved in radio frequency transmission and electromagnetic field analysis will benefit from this discussion.

Noone1982
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If a radio station transmits at 500 kW, how does one find the electric field 25 kM away?
 
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The energy emitted by the source in dt is Pdt
where P=500\,kW. At R=25\,km from the source this energy will be uniformly distributed in a spherical shell of radii R and R+dR. The volume of this shell equals
dV=\pi R^2 c dt
where c is the speed of light. Now you have to know that the energy density of an electromagnetic wave can be written as
w=\frac{1}{2}\epsilon_0 E^2
with E the elecric field amplitude. So
P dt=w\cdot dV
... and you find E!
 
Last edited:

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