Finding an element using quantum configuration

In summary, you counted the number of electrons in the element [Xe]4f14+4, and then added 4 to account for the loss of electrons.f
  • #1
8
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Please post this type of questions in the homework section using the template and showing your work.
havent done this stuff in lile 5-6 years so can't remember half of what to do lel.
the first part i would like a yes/no please, Thanks. Given the quantum numbers (6,2,2,+1/2) what is the element, i said UUB becasue the first two numbers indicate 6D and the second would mean its +2 and positive spin so 6D9 which would indicate UUB?

The actual question I am having problems with is gven [Xe]4f14+4 whatis the element

Thanks.
 
  • #2
Quantum numbers alone don't say anything about the element, they characterize an electron which can be present in any (excited need be) element. Is it an outermost electron?

[Xe]4f14+4

How many electrons in a neutral atom of that element?
 
  • #3
Thats all that was given, this is why this qustion is dumb, it literally says an element with the electron configurtion [Xe]4F14+ is what? so i when to Xe and then to the F block counted 14, minused 4 bcasue of the + 4,

And was the first part Right?

thanks.
 
  • #4
Actually the later part (the one with [Xe]4f14+4) is perfectly OK. It was the first part of your post (6,2,2,+1/2) that didn't make sense.

so i when to Xe and then to the F block counted 14, minused 4 bcasue of the + 4

Can you translate it into English?
 
  • #5
6 represnt the principal quantum number, the first 2 is the angular momentum quantum number, the second two is the magnetic , and the =1/2 is the spin. so for this I am pretty sure, it would be 6D5 becasue the 6 principal quantum number and the first means a D orbital, and then it should be 6D5 becasue it has a potive spin and is i is 5 becasue the other 2nd two is the 2 for number of orbitals ( -2, -1, 0, 1, 2) so there are 5 electrons so there are 5 electrons so this should be 6D5

for the [Xe] part ment to say, started at xenon on the periodic table, because the quantum number is [Xe] 4f14, then i proceeded to the 4f block, and counted 14 elements becasue it is [Xe] 4f14 then minues 4 becasue it is +4 [Xe] 4f14+4. I am not sure if this makes sense, and I am almost 100% positive this is wrong.
 
  • #6
If it was a neutral atom, it would have four more electrons than the 4+ ion, so you count the 14, then add another 4.
 
  • #7
how would that work, plus 4 indicates loss of electrons since lectrons are negative, your implying that if an atom is neutral and then I become a positively charged ion i gained 4 electrons??
 
  • #8
How many electrons do you need to add to Na+ to make it neutral?

How many electrons do you need to add to Mg2+ to make it neutral?

How many electrons do you need to add to Al3+ to make it neutral?

How many electrons do you need to add to Whatever4+ to make it neutral?
 
  • #9
I think i understand so i did it and got Hafnium for my answer?
 
  • #10
Looks OK.
 

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