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Finding an equation for a plane containing 3 points

  1. Sep 30, 2017 #1

    yecko

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    1. The problem statement, all variables and given/known data
    螢幕快照 2017-09-30 下午3.37.01.png

    2. Relevant equations
    https://answers.yahoo.com/question/index?qid=20120204205204AAEvo8V

    3. The attempt at a solution
    771152855.jpg

    This is my attempt following the solution in the yahoo answer, yet it is incorrect...
    Can anyone tell me if I have made mistake in any of the manipulation?
    Any help is appreciated~~
    Thanks!!!
     
  2. jcsd
  3. Sep 30, 2017 #2

    Orodruin

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    You should double check your algebra.
     
  4. Sep 30, 2017 #3

    yecko

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    I just multiplied the whole equation by -3 and manipulated all the signs... after i checked several times, i still can't find what is wrong...
     
  5. Sep 30, 2017 #4

    Orodruin

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    Your algebra. You are not adding and multiplying correctly.

    Write out every step.
     
  6. Sep 30, 2017 #5

    ehild

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    Check the determinant.
     
  7. Oct 1, 2017 #6

    Mark44

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    @yecko, when you calculate a cross product, it's a good idea to make sure that the vector you get is actually perpendicular to the two input vectors you're working with. This can be done very quickly, using the dot product. In the work you did, your calculated cross-product is <2, 2, -1>. This vector isn't perpendicular to either of the other two vectors, which means your calculation is incorrect.
     
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