Finding Angles for Conic Section

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SUMMARY

The discussion focuses on finding angles for rotating a hyperbola represented by the equation x² + 4xy + y² = 12. The user initially attempts to apply the standard formula (A-C)/B but encounters a zero result, indicating a need for a different approach. The correct method involves diagonalizing the symmetric matrix A = [[1, 2], [2, 1]] associated with the conic section. This technique is essential for determining the rotation angles necessary for transforming the hyperbola into its standard form.

PREREQUISITES
  • Understanding of conic sections, specifically hyperbolas
  • Knowledge of matrix diagonalization techniques
  • Familiarity with symmetric matrices
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the process of diagonalizing symmetric matrices in linear algebra
  • Learn about the standard forms of conic sections and their transformations
  • Explore the geometric interpretation of rotation angles in conic sections
  • Investigate applications of conic sections in physics and engineering
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Mathematicians, students studying conic sections, and anyone interested in advanced algebraic techniques for analyzing and transforming geometric shapes.

splac6996
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I have a hyperbola with the following equation and I am trying to find my angles to eventually rotate this (conic section), but I don't know what to do because when I follow the standard form of (A-C)/B, I get zero. Is there some trick that I don't know about.

x^2+4xy+y^2=12
 
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First, you can write the equation in this way
[tex] \left[ \begin{array}{cc}<br /> x & y<br /> \end{array} \right]<br /> \cdot<br /> \left[ \begin{array}{cc}<br /> 1 & 2 \\<br /> 2 & 1<br /> \end{array} \right]<br /> \cdot<br /> \left[ \begin{array}{c}<br /> x \\ y<br /> \end{array} \right] = 12[/tex]

Now, you have to diagonalize the symmetric matrix
[tex] A = \left[ \begin{array}{cc}<br /> 1 & 2 \\<br /> 2 & 1<br /> \end{array} \right][/tex]

Then, see this!
 
I have never seen this technique before is that the only way to do this?
 

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