Finding Angles in a Double slit experiment

Click For Summary
SUMMARY

The discussion focuses on calculating angles for bright fringes in a double slit experiment using the formula d\sin \theta = m\lambda. Participants clarify that for different wavelengths, such as 500 nm and 600 nm, separate calculations must be performed, resulting in two distinct sets of fringes. The value of m represents the order of the fringe and can take values of 0, 1, 2, etc. Participants agree on providing angle values for m = 0, 1, 2 for each wavelength.

PREREQUISITES
  • Understanding of the double slit experiment
  • Familiarity with the formula d\sin \theta = m\lambda
  • Basic knowledge of wavelength measurements (e.g., nanometers)
  • Concept of constructive interference in wave physics
NEXT STEPS
  • Research the implications of varying wavelengths in interference patterns
  • Learn about the significance of fringe order in double slit experiments
  • Explore practical applications of the double slit experiment in modern physics
  • Investigate how to measure angles in experimental setups accurately
USEFUL FOR

Students of physics, educators teaching wave interference, and researchers interested in experimental physics methodologies.

jisbon
Messages
475
Reaction score
30
Homework Statement
A point light source is used in a double-slit experiment. The light source contains 2 wavelengths (500nm and 600nm). Separation of the 2 silts is d=1mm. 2 sets of interference fringes are formed on the screen. Find the angles where the bright fringes are formed for both of the wavelengths.
Relevant Equations
##d\sin \theta =m\lambda##
1579006899965.png

Hello all!


Having some problems understanding this question.
From what I know, bright fringes means that there will be constructive interferences, whereby ##d\sin \theta =m\lambda##
In this case, I know the d (separation of silts). However, what should I put in for wavelength? I went through some examples online and they all showed sources projecting the same wavelength. In cases of different wavelength like the one above, how should I proceed? Cheers
 
Physics news on Phys.org
Do two separate calculations, one for 500 nm and one for 600 nm. There will be two sets of fringes.
 
mjc123 said:
Do two separate calculations, one for 500 nm and one for 600 nm. There will be two sets of fringes.
Thanks for the fast reply. What should I input for m? I understand that for bright fringes, m can be = 0,1,2,3.. etc. So in this case, how do I determine the value of m? Cheers
 
It asks for angles (plural) but doesn't say how many. I would give values for m = 0, 1, 2 for each wavelength.
 
  • Like
Likes jisbon
Oh okay, thanks for the help :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
6K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K