A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the water land 2.0 m away? Why are there two different angles?
ay= 9.80 m/s/s
y= I'm guessing 0, because it lands on the ground at approximately the same level..
x = Vx0t
Vx0 = 6.8 cosθ
Vyo= 6.8 sinθ
y= y0 + Vyot - 1/2ayt2
The Attempt at a Solution
Oh my god. I have no idea why I'm having so much trouble with this problem. I've been trying to solve this for about two hours. I've re-written the equations in my book multiple times and I don't know how to solve this. I've been trying to solve for the time but there are so many variables.. I'm not even really familiar with cosine and sine. The problem implies that there are two angles in the answer. So I'm guessing it's because there's some sort of quadratic equation involved. I don't know. :/
I even tried to find a way to use substitution and find the time, but it was no use. Please, help! :'(