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1) Given: two ropes of negligible weight suspend an object weighing 50N from the ceiling There are two angles of PHI that form from as a measure from the vertical. PHI_{1} + PHI_{2}= 60°. The tension of the left rope is given to be 80N and the tension of the left rope is given to be 70N. The entire system is stationary.
2) Find the measures of each angle PHI as well as each complimentary θ.
3) I tried to use ƩF=0=T_{1} + T_{2} + (Fg)
∴ 50N = 80N*cos(60PHI_{1}) + 70N*cos(60PHI_{2})
I couldn't think of a way to solve this by hand so I tired to use my Ti84 calculator's equation solver and got PHI values of 10° and 50°. Logically, this doesn't make sense. My teacher decided to just omit the question, but I am still curious as to how it would actually be done.
2) Find the measures of each angle PHI as well as each complimentary θ.
3) I tried to use ƩF=0=T_{1} + T_{2} + (Fg)
∴ 50N = 80N*cos(60PHI_{1}) + 70N*cos(60PHI_{2})
I couldn't think of a way to solve this by hand so I tired to use my Ti84 calculator's equation solver and got PHI values of 10° and 50°. Logically, this doesn't make sense. My teacher decided to just omit the question, but I am still curious as to how it would actually be done.
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