Finding average acceleration from data points of a velocity time graph?

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To find the average acceleration from a velocity-time graph, the key is to calculate the net change in velocity over the time interval. The average acceleration can be determined using the coordinates of the data points at the start and end of the interval, specifically at 0 seconds and 50 seconds. The slope of the secant line between these two points represents the average acceleration. No need for fitting a line or deriving an equation; simply use the given data points. This straightforward approach clarifies the concept of average acceleration effectively.
TexasCow
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Well I posted this in the calculus section but think it would be answered easier here since it's mild calculus if any.

1. Homework Statement
I'm studying for a Calculus test and I am having trouble on a problem. And who better to ask than the members of physicsforums!?

Basically, we are studying average acceleration, velocity, secant and tangent lines. We are given the graph of a function, and its corresponding data points.

The question asks:
"Find the average acceleration of the car, in f/s, over the interval 0<t<50.(The inequality signs are acutally "less than or equal to", but I don't know how to input such characters.)

I'm aware that the derivative of a velocity time graph is its acceleration/time graph. So I assume that the slope of the line is the acceleration. Unfortunately, we are not permitted to fit a best line, or derive an equation. Is there another way of doing this? Thanks for any help.
 
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The average acceleration is simply the net change in velocity over the corresponding change in time. You just need to coordinates of the two data points at 0 and 50 s.

This is the easy one.
 
Wow, I just realized. I feel so dumb! Thanks a bunch.
 

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