1. For the circuit shown, (a) Find the current in each resistor (b) Find the potential difference between c and f 2. Relevant equations: i2 + i1 = i3 i = V/R 3. (a) So solving for each resistor using the loop rule this is what I got, (Resistor 3): E3 - IR3 = -E2 - E1 (Resistor 2): -E2 - IR2 = E3 - IR3 (Resistor 1): -E1 - IR1 = E3 - IR3 Then plugging in for the givens I got: I3 = 52.5 kA I2 = 1.67 kA I1 = 2.49 kA I'm trying to follow my notes the best I can, but I am not seeing any examples like this in my notes or in the text. I hope I'm at least on the right path. (b) So since the there are two different paths that could be taken to reach f from c I used the equation V=iR to get: (I3 - I2) R2 = the potential difference from c to f through battery 1 (I3 - I1) R1 = the potential difference from c to f through battery 2 I then subtracted the potential differences from each other to give me the overall potential difference at f. Again, nothing in my notes or in the text are very helpful, so this is just based on the formulas I know. Thank you in advance for the help.