Finding current in a circuit using Kirchhoff voltage law

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The discussion revolves around applying Kirchhoff's voltage law to solve a circuit problem, where the ammeter reads 2 A. The user sets up the equation based on the law but finds their calculated current, I1, to be -0.714 A, which conflicts with the provided solution that does not include a negative sign. Other participants suggest the user may have made an algebra mistake and emphasize the importance of posting the complete circuit for accurate analysis. The conversation highlights the necessity of careful equation setup and verification in circuit analysis. Accurate representation of the circuit is crucial for resolving discrepancies in solutions.
wanderer0102
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Homework Statement


Hi, I'm learning about Kirchhoff's laws, and have to solve the circuit. Attached picture of part the circuit I am attempting to solve. The ammeter reads 2 A.

Homework Equations


Kirchhoff's voltage law says the total voltage around a closed loop must be zero.

The Attempt at a Solution


By going around the loop I get 0 = -18V + (7 ohms)(I1) + (5 ohms)(2 A) + 3V.
Then solving for the current I1 I find that it is -0.714 A. But in the solution it does not have a negative sign. What did I do wrong?
 

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wanderer0102 said:
0 = -18V + (7 ohms)(I1) + (5 ohms)(2 A) + 3V.
...
But in the solution it does not have a negative sign. What did I do wrong?
Algebra mistake? Your equation gives a positive value, +5/7

But you did not even post the full circuit :\
 
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