Finding degeneracy of N Quantum Harmonic Oscillator

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SUMMARY

The discussion focuses on calculating the total degeneracy of N 3-D Quantum Harmonic Oscillators. The degree of degeneracy for a single 3-D harmonic oscillator is defined by the formula (n+1)(n+2)/2. To find the total degeneracy across N oscillators, one must sum the degeneracy equation from n(i) for i=1 to 3N. The total energy is expressed as the sum of E(i) from i=1 to 3N, where E(i) is given by ((n(i)+0.5))*(hbar)w. The participants emphasize the need to clarify the problem's wording and the summation limits.

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  • Understanding of Quantum Harmonic Oscillator principles
  • Familiarity with the concept of degeneracy in quantum mechanics
  • Knowledge of energy quantization in quantum systems
  • Basic proficiency in mathematical summation techniques
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  • Research the derivation of the degeneracy formula (n+1)(n+2)/2 for 3-D Quantum Harmonic Oscillators
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Physicists, quantum mechanics students, and researchers working on problems related to Quantum Harmonic Oscillators and their degeneracies.

Sekonda
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Hey guys,

For a particular problem I have to determine the total degeneracy across N 3-D Quantum Harmonic oscillators.

Given that the degree of degeneracy for a 3-D harmonic oscillator is given by:

(n+1)(n+2)/2

and the Total energy of N 3d quantum harmonic oscillators is given by the sum of E(i) from i=1 to 3N, or the sum of ((n(i)+0.5))*(hbar)w.

I think I need to sum the degeneracy equation from n(i) i=1 to 3N to find the total number of degeneracies but I'm not sure what sum this reduces to!

Thanks,
Tom
 
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Why exactly are you summing up to 3N when you have N harmonic oscillators? To get the energy of a certain state you should add the energy of all the oscialltors right. Then this is summation until N. For every one of these N things there are (n+1)(n+2)/2 different states that yield the same energy. Now you will need explicitly the energies to see in how many ways you can add N energies to get the same one. Then mulitply that by the degeneracy of 1 to the third power.

That is how I would do it at least.
 
Last edited:
Indeed, that is how I thought the problem should be worded. However the problem seems to be set out in an unfamiliar way and I'm not quite sure what is meant by the problem at all!

Though, from what you've said is what I've read around various places of the internet. Oh well, will just have to wait and see what the solution is and try and make sense of it then!

Thanks again conquest,
S
 

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