Finding Derivatives with the Multivariable Chain Rule

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Homework Help Overview

The discussion revolves around finding derivatives using the multivariable chain rule, specifically for the function z = f(x + 2y). Participants are tasked with showing that 2∂z/∂x − ∂z/∂y = 0.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of the multivariable chain rule, questioning how to express ∂z/∂x and ∂z/∂y in terms of f' and the function g(x,y) = x + 2y.

Discussion Status

Some participants have provided guidance on how to approach the derivatives, with one confirming the expression for ∂z/∂x and prompting further exploration of ∂z/∂y. The discussion appears to be progressing with collaborative input.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the extent of their discussions and the depth of exploration into the problem.

Doug_West
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Homework Statement



Let f be a differentiable function of one variable, and let
z = f(x + 2y). Show that
2∂z/∂x − ∂z/∂y = 0

Homework Equations



Multi-variable chain rule

The Attempt at a Solution



I have no idea where to start with this, any advice would be greatly appreciated.

Thanks in advance,
Doug
 
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Doug_West said:

Homework Statement



Let f be a differentiable function of one variable, and let
z = f(x + 2y). Show that
2∂z/∂x − ∂z/∂y = 0

Homework Equations



Multi-variable chain rule

The Attempt at a Solution



I have no idea where to start with this, any advice would be greatly appreciated.

Thanks in advance,
Doug

z=f(g(x,y)), where g(x,y)=x+2y. Now what does the chain rule tell you about, say ∂z/∂x?
 
would it be f'(g(x,y))*1?
 
Doug_West said:
would it be f'(g(x,y))*1?

Yes! Now do ∂z/∂y.
 
f'(g(x,y)))*2
 
So 2∂z/∂x − ∂z/∂y equals what?
 
0! Thanks for the help.

Doug.
 

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