Finding Dipole Moment: Solve Integral & Calculate \vec p

Click For Summary
SUMMARY

The discussion focuses on calculating the dipole moment \(\vec p\) for a sphere with a surface charge density \(\rho_s = k \cos \theta\). The integral for the dipole moment is given by \(\vec p = \int \vec r' \rho_s \; d a\), which simplifies to \(\vec p = \hat z p\) when considering the charge distribution. The key insight is that resolving the vector \(\vec r'\) into its x, y, and z components allows for the cancellation of the x and y components, leading to the correct calculation of \(\vec p\). The discussion concludes with a confirmation of understanding from the participants.

PREREQUISITES
  • Spherical coordinates
  • Surface charge density concepts
  • Vector calculus
  • Integral calculus
NEXT STEPS
  • Study the derivation of dipole moments in electrostatics
  • Learn about spherical harmonics and their applications
  • Explore vector integration techniques in polar coordinates
  • Investigate the physical significance of dipole moments in electromagnetism
USEFUL FOR

Students and professionals in physics, particularly those focusing on electrostatics and electromagnetic theory, as well as anyone involved in advanced calculus and vector analysis.

yungman
Messages
5,741
Reaction score
291

Homework Statement



Given a sphere radius R with surface charge density [itex]\rho_s=k\;cos\theta[/itex]. Find the dipole moment [itex]\;\vec p[/itex].

Homework Equations



[tex]\vec p=\int \vec r'\rho_s \;d a = \int_0^{2\pi}\int_0^{\pi}\vec r' k\;cos\theta\; R^2d\theta\;d\phi[/tex]

The Attempt at a Solution



To me, [itex]\vec r' = \hat R R[/itex] in spherical coordinates. But the book claimed from the charge density distribution, [itex]\vec p = \hat z p[/itex] which make sense so the book assumed [itex]\;\vec r'=\hat z z = \hat z R\;cos\theta[/itex]. This all make sense.

My real question is what if I don't know the direction of the [itex]\vec p[/itex] by looking at the charge distribution, how am I going to do the integration and find [itex]\vec p[/itex]? If I just use [itex]\vec r' = \hat R R[/itex], the answer won't be correct. Please help.
 
Physics news on Phys.org
Resolve the vector r into x, y, and z components, expressed in polar coordinates and calculate these components by separate integrals. You will see that both the x and y components cancel.

ehild
 
ehild said:
Resolve the vector r into x, y, and z components, expressed in polar coordinates and calculate these components by separate integrals. You will see that both the x and y components cancel.

ehild

I got it, thanks for your help.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
10
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
26
Views
6K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K