Finding displacement from variable acceleration

In summary, the problem is trying to show that a car, after traveling a certain distance x, will have a certain velocity v, using given equations and attempting to integrate. The attempt so far has been to substitute in a = d/dx(0.5v2) and then integrate with respect to x, but without success. Any help is appreciated.
  • #1
TPHughes
1
0
Hello, I've been staring at this question for an hour with no luck.. if anyone could point me in the right direction that would greatly appreciated!

Homework Statement



a = acceleration
v = velocity
x = displacement
m and n are constants
vt = terminal velocity

Show that after traveling x, car will have velocity v.


Homework Equations



a = m - nv2 <- given equation

and vt = sqrt(m/n)

x = -0.5ln(1 - (v/vt)2) <- equation need to find

The Attempt at a Solution



I have attempted to substitute in a = d/dx(0.5v2) and then integrate with respect to x but had no luck.

Am stuck with where to go next! Any help would be greatly appreciated!
 
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  • #2
Welcome to PF!

Hello TPHughes! Welcome to PF! :smile:
TPHughes said:
a = m - nv2 <- given equation

vdv/(m - nv2) = dx :wink:
 

1. How is displacement calculated from variable acceleration?

In order to find displacement from variable acceleration, you will need to use the equation: Δx = v0t + 1/2at2, where Δx represents displacement, v0 represents initial velocity, a represents acceleration, and t represents time.

2. Can displacement be negative when calculating from variable acceleration?

Yes, displacement can be negative when calculating from variable acceleration. A negative displacement indicates that the object has moved in the opposite direction of its initial position.

3. What units should be used when calculating displacement from variable acceleration?

Displacement is typically measured in meters (m) when using the standard metric system. However, any unit of length can be used as long as it is consistent throughout the calculation.

4. How does changing acceleration affect displacement?

Changing acceleration affects displacement by altering the rate at which an object is moving. The greater the acceleration, the faster the object will change its position, resulting in a larger displacement.

5. Can displacement be calculated if the acceleration is unknown?

No, displacement cannot be accurately calculated if the acceleration is unknown. In order to find displacement, you must have at least two known variables, such as initial velocity, time, or acceleration.

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