1. The problem statement, all variables and given/known data 2. Relevant equations Kinematic equations t = 18s when the velocity is back to 54km/h or 15m/s at t = 2, V = 13.3 m/s at t = 4.5, velocity is 1.5 m/s at t = 1, V = 15m/s 3. The attempt at a solution I have solved the first part and I have the time at which it is 54km/h again, but now I'm trying to figure out the position. I think I could make a v-t graph and find the area under that curve, but it seems like that would be too hard to accurately represent the graph. Is there any other way to find displacement? I've tried xo = vot + 1/2at2 but that doesn't seem to help I also tried x = xo + vt, but I get 270m as an answer. The correct answer is 178.8, but I just want to understand how to do it. Any help would be much appreciated!