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## Homework Statement

3. A baseball (m = 0.150 kg) is thrown with an initial speed of 30.0 m/s at an angle of 37.0 degrees from the horizontal at y = 0 m. (a) Find the initial KE of the ball. (b) Use conservation of energy (not kinematic equations) to find the maximum height reached by the ball. (Hint: Does the ball have any velocity at its maximum height?)

## Homework Equations

KE

_{f}+ U

_{f}= KE

_{i}+ U

_{i}

(.5)mv

_{f}² + mgy

_{f}= (.5)mv

_{i}² + mgy

_{i}

## The Attempt at a Solution

(a) Part a I got the correct answer, but can you tell me if I did it the correct way. I did (.5)(0.15)(30)² = 67.5J

(b) What I tried was using KE

_{f}+ U

_{f}= KE

_{i}+ U

_{i}. For the velocity at the top I accounted for the angle and got that the velocity in the x direction was 24.0m/s So I did:

(.5)(0.15)(24.0)² + (.5)(9.8)y = 67.5 (from part a) + (0.15)(9.8)(0)

Solving for y I get 4.96m, but that is not the correct answer. I'm not sure if I am doing it the wrong way or if I made some error somewhere, so any help would be appreciated.

Thanks