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Finding downward force on immersed object
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[QUOTE="haruspex, post: 6866551, member: 334404"] I cannot see the point of splitting the buoyancy into a downward force F[SUB]i[/SUB] on the top of the object and an upward force F[SUB]j[/SUB] on the bottom. In general, it would be very difficult to separate it like that; only for objects with horizontal surfaces top and bottom and vertical sides. Even then, you’d have to measure the depth at top and bottom. You don't need to that to solve the problem, just handle it as B. Next, the last equation above seems like nonsense if the terms have the meanings you have stated. First, where did the minus sign come from? It appears B is positive up, so the equation would give a negative density. Secondly, how did B turn into F[SUB]i[/SUB]-F[SUB]g[/SUB]? You remark that T is taken to be zero, but since you have not defined T I cannot comment on that. Here's how it should work: You know the tension in the cable supporting the net. I will call that T. ##B+T=mg##. ##\rho_{object}=\rho_{water}\frac{mg}B=\rho_{water}\frac{mg}{mg-T}##. From that, it seems to me that your equation is using ##F_i## for the tension in the cable and ##F_j## to mean the same as ##F_g##, which is the same as mg. [/QUOTE]
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Finding downward force on immersed object
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