- #1

- 180

- 8

Ok, so we know that [itex]x=rcos(\theta)[/itex]

So what is dx?

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Furthermore, can I get dS in polar by finding dx and dy in polar and then substituting them into dS for rectangular? Is there an easier way to solve for dS in polar?

So what is dx?

***

Furthermore, can I get dS in polar by finding dx and dy in polar and then substituting them into dS for rectangular? Is there an easier way to solve for dS in polar?

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