Finding eigenlines & eigenvalues

  • Thread starter Thread starter Roodles01
  • Start date Start date
  • Tags Tags
    Eigenvalues
Click For Summary

Homework Help Overview

The discussion revolves around finding eigenlines and eigenvalues of a given matrix, specifically focusing on the algebraic manipulation involved in deriving simultaneous equations from the eigenvector equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the process of substituting eigenvalues into the eigenvector equation and the resulting simultaneous equations. There is confusion regarding how these equations reduce to a single equation. Some participants express uncertainty about their algebra and seek clarification on the reduction process.

Discussion Status

Some participants have made progress in understanding the reduction of equations, while others are still grappling with the algebra involved. There is an acknowledgment of the need to verify the eigenvalues and the original matrix, indicating a productive exploration of the problem.

Contextual Notes

Participants are working with a specific matrix and eigenvalues, and there is mention of previous examples that led to simpler reductions. The discussion includes questioning the validity of certain eigenvalues based on the provided matrix.

Roodles01
Messages
125
Reaction score
0
In my example I have matrix A = (1 2)
. . . . . . . . . . . . . . . . . . . . . . (3 2)

Finding the eigenvalue through the method I understand & can get the result

i.e.
k = 4 & -1

I suspect my algebra is the shaky link, here, but to find the eigenline I find a bit more of a challenge.

OK I start by substituting the eigenvalue into the eigenvector equation;
Ax = kx
giving
(1 2) (x) = 4 (x)
(3 2) (y)...(y)


which gives rise to the following simultaneous equations
x + 2y = 4x
3x + 2y = 4y

Now the bit I don't get . . .
How do these both reduce to 3x - 2y = 0

I'm sure it's simple & I can't see the wood for the trees, but this is stupidly defeating me.. . . . Grrr!

Please could someone point me in the right direction.
 
Last edited:
Physics news on Phys.org
Damn, it's so easy to suddenly see the solution.
OK I'm done

x + 2y = 4x
3x+ 2y =4y

goes to
-3x + 2y = 0
3x - 2y = 0

both reduce to
3x - 2y = 0

Thank you.
 
All the other examples I have had led to the simultaneous equations reducing to a single equation, from which I can find the eigenline equation for each eigenvalue (2 in this case).

The simultaneous equation I have now is;
3/4 x - 3/4 y = 0
-1/4 x - 1/4 y = 0

I am assuming I have the negative value wrong, but I may not, I suppose, so how can I get back to a single equation so I can find the eigenline equation for each eigenvalue.
 
Please tell us what the matrix in this problem is so that we can tell whether or not 2 really is an eigenvalue.
 
(11/4 -3/4)
(-1/4 9/4)

This is the original matrix. Thank you.
 
Roodles01 said:
All the other examples I have had led to the simultaneous equations reducing to a single equation, from which I can find the eigenline equation for each eigenvalue (2 in this case).

The simultaneous equation I have now is;
3/4 x - 3/4 y = 0
-1/4 x - 1/4 y = 0

I am assuming I have the negative value wrong, but I may not, I suppose, so how can I get back to a single equation so I can find the eigenline equation for each eigenvalue.

based on the matrix you provided, the second equation should be:

-(1/4)x + (1/4)y = 0.

thus BOTH equations lead to:

x = y.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
Replies
2
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
20K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K