Finding eigenvalues and eigenvectors

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fargoth
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is there any trick for finding the eigenvalues and vectors for this kind of matrix?
[tex] \left(<br /> \begin{array}{ccccc}<br /> 0 & 1 & 0 & 0 & 0 \\<br /> 1 & 0 & \sqrt{\frac{3}{2} & 0 & 0 \\<br /> 0 & \sqrt{\frac{3}{2} & 0 & \sqrt{\frac{3}{2} & 0 \\<br /> 0 & 0 & \sqrt{\frac{3}{2} & 0 & 1 \\<br /> 0 & 0 & 0 & 1 & 0 \\<br /> \end{array}<br /> \right)[/tex]

i mean, i can tell the eigenvalues are 2,1,0,-1,-2... and i can tell the eigenvectors would have a=e and b=d... but that's because i know what this matrix is... but if i'll see some matrix with different values then this roaming around... i don't know what i'll do, i don't think trying to solve the standard polynom of it is a good idea... and after knowing the eigenvalues one has to solve the set of equations to find the eigenvectors -yuck!-
 
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Well it's a symmetrical matrix so it's surely diagonalizable.
I don't see any special 'trick' although the classical way (add [itex]-\lambda[/itex] on the main diagonal and compute the determinant) shouldn't be too hard thanks to the many 0's... (e.g. expand the determinant to the first row or column).
 
yeah, I am just REALLY lazy :-p
i thought there's a trick that would make me see in a sec the right solution...
i only know the trick for block diagonal, and its not useful here...
 
Perhaps there is, but I then I don't know it :smile:

If you know the (normal) method and you're only interested in the solution, why not use a computer program?
 
well, the advantage of knowing helpful shortcuts is that you develop some intuition, which is pretty useful...

for example, if i got a block diagonal matrix i know the different blocks are orthogonal, which means vectors with parts that belong only to a certain block would stay in that block... and that's why i can find eigenvectors separately for each block.
 
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Of course, it was just a suggestion if you were only looking for the answer.
It's by far a better choice to do it yourself, if you wish to develop your mathematical intuition :smile: