Finding eigenvalues and eigenvectors

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Homework Help Overview

The discussion revolves around finding eigenvalues and eigenvectors of a specific matrix, which is noted to be symmetrical. Participants express concerns about the complexity of the standard polynomial method for determining eigenvalues and the subsequent equations needed for eigenvectors.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the classical method of adding -λ to the diagonal and computing the determinant, while some express frustration with the process. There are mentions of potential shortcuts and the usefulness of intuition developed through understanding matrix properties, such as block diagonal matrices.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on the methods available for finding eigenvalues and eigenvectors. Some suggest using computational tools for quick solutions, while others emphasize the importance of understanding the underlying concepts for developing mathematical intuition.

Contextual Notes

One participant notes a lack of effective shortcuts for the given matrix type, and there is a general acknowledgment of the challenges posed by the standard methods of solving for eigenvalues and eigenvectors.

fargoth
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is there any trick for finding the eigenvalues and vectors for this kind of matrix?
[tex] \left(<br /> \begin{array}{ccccc}<br /> 0 & 1 & 0 & 0 & 0 \\<br /> 1 & 0 & \sqrt{\frac{3}{2} & 0 & 0 \\<br /> 0 & \sqrt{\frac{3}{2} & 0 & \sqrt{\frac{3}{2} & 0 \\<br /> 0 & 0 & \sqrt{\frac{3}{2} & 0 & 1 \\<br /> 0 & 0 & 0 & 1 & 0 \\<br /> \end{array}<br /> \right)[/tex]

i mean, i can tell the eigenvalues are 2,1,0,-1,-2... and i can tell the eigenvectors would have a=e and b=d... but that's because i know what this matrix is... but if i'll see some matrix with different values then this roaming around... i don't know what i'll do, i don't think trying to solve the standard polynom of it is a good idea... and after knowing the eigenvalues one has to solve the set of equations to find the eigenvectors -yuck!-
 
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Well it's a symmetrical matrix so it's surely diagonalizable.
I don't see any special 'trick' although the classical way (add [itex]-\lambda[/itex] on the main diagonal and compute the determinant) shouldn't be too hard thanks to the many 0's... (e.g. expand the determinant to the first row or column).
 
yeah, I am just REALLY lazy :-p
i thought there's a trick that would make me see in a sec the right solution...
i only know the trick for block diagonal, and its not useful here...
 
Perhaps there is, but I then I don't know it :smile:

If you know the (normal) method and you're only interested in the solution, why not use a computer program?
 
well, the advantage of knowing helpful shortcuts is that you develop some intuition, which is pretty useful...

for example, if i got a block diagonal matrix i know the different blocks are orthogonal, which means vectors with parts that belong only to a certain block would stay in that block... and that's why i can find eigenvectors separately for each block.
 
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Of course, it was just a suggestion if you were only looking for the answer.
It's by far a better choice to do it yourself, if you wish to develop your mathematical intuition :smile:
 

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