Finding Electric Energy Density

[stylez03]

Homework Statement

Find the electric-field energy density at a point which is a distance of 10.0 cm from an isolated point charge of magnitude 7.30 nC.

Homework Equations

u = \frac {1} {2} * e_{o} * E^{2}

The Attempt at a Solution

u = \frac {1} {2} * 8.85*10^{-12} * 7.30^{2}

This was the equation we learned in class, and the online program say's its wrong. From the book it says that factors of A and d cancel out because of geometry, though I'm second guessing now, since the book says the equation is only in a vacuum, but this problem doesn't state either or?

 

[Dick]

First you want to know what the value for E is in that situation. What formula might you use for that?

 

[stylez03]

First you want to know what the value for E is in that situation. What formula might you use for that?

The only equation from this chapter that I could find that would be relevant and give you E would be:

V_{ab} = E*d

E = \frac {V_{ab}} {d} ?

 

[Dick]

It's the electric field around a POINT charge. It HAS to be one of the first formulas you encounter. Hint: it's an inverse square law. Keep looking.

 

[stylez03]

It's the electric field around a POINT charge. It HAS to be one of the first formulas you encounter. Hint: it's an inverse square law. Keep looking.

E = sigma / e_o ?

 

[Dick]

E = sigma / e_o ?

Nope. E=??/r^2. What's the numerator?

 

[stylez03]

Nope. E=??/r^2. What's the numerator?

ooh E = \frac {KQ} {R^{2}}

I was thinking about this one but I thought you just meant in this chapter.

Q = 7.30 * 10^-19 ?

 

[Dick]

ooh E = \frac {KQ} {R^{2}}

I was thinking about this one but I thought you just meant in this chapter.

Q = 7.30 * 10^-19 ?

You don't have units on Q. I can't tell you if it's right. It's given as 7.30 nC. How many coulombs is that?