Finding energy produced in nuclear fusion

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SUMMARY

The forum discussion centers on calculating the energy produced from the fusion reaction H(2,1) + H(3,1) -> He(4,2) + n(1,0). The energy output for 150 kg of hydrogen isotopes is determined to be 5.07 x 10^16 J. To arrive at this conclusion, participants emphasize the importance of calculating the mass difference between the reactants and products, followed by applying Einstein's equation E=mc² to find the energy released. The atomic masses provided for each isotope are crucial for accurate calculations.

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  • Understanding of nuclear fusion reactions
  • Familiarity with atomic mass units (Ar)
  • Knowledge of Einstein's equation E=mc²
  • Basic skills in mass-energy conversion calculations
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Homework Statement


In a proposed fusion reactor, one possible reaction is H(2,1) + H(3,1) -> He(4,2) + n(1,0)

How much energy might 150kg of the appropriate amount of isotopes of hydrogen produce?

Values given
Ar of H(2,1) = 2.014102
Ar of H(3,1) = 3.016050
Ar of He(4,2) = 4.002602
Ar of n(1,0) = 1.008665

Homework Equations


E=mc^2?


The Attempt at a Solution


The correct answer is 5.07 x 10^16 J but I can't seem to get it. Any help is appreciated thanks.
 
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Start by figuring out the mass difference between the two sides of the reaction and multiply by c^2. Then figure out how many times you have to run that reaction to use up 150kg of H(2,1) + H(3,1).
 

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