Finding Equations of Tangents and Intersection Points for y=(2x-1)(x+1)

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SUMMARY

The discussion focuses on finding the equations of tangents and intersection points for the curve defined by the equation y=(2x-1)(x+1). The recommended approach is to first determine the x-values where the curve intersects the x-axis by setting y=0, followed by calculating the derivative at those x-values to find the tangent equations. This method ensures accurate tangent calculations at the intersection points.

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additional maths help please!

My minds gone blank. How do I solve this
Find the equations of the tangents to the curve y=(2x-1)(x+1) at the points where the curve cuts the x axis. Find the point of intersection of these tangents.
Thanks
Emmab
 
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First find the tangent equation using differentiation, then find the points where the curve cuts the x-axis and plug in.
 


I would be inclined to do it the other way around! First find the x-values where the curve crosses the x-axis (y= 0 there), then find the derivative at those values of x. No real difference, of course.
 

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