Finding Expected Lateral Displacement From a Risley Prism

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SUMMARY

The discussion focuses on calculating the expected lateral displacement of light using a Risley prism setup. The measured displacements for powers of 3° and 6° were 1.80 cm and 3.51 cm, respectively, with a distance of 62.2 cm from the prism to the measurement point. The formula used is P = 100(x/b), where P is the power and x is the displacement. The user expressed confusion regarding the necessity of recording the 3° reading and the relevance of the formulas involving 2P and 2Psinθ.

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  • Understanding of optical physics, specifically prism optics
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  • Research the effects of prism angles on light displacement, particularly the 2P and 2Psinθ relationships
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Pythia
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Homework Statement


Find the expected lateral displacement for a spot of light at a power of [itex]6^{∆}[/itex].

Distance from prism to where displacement was measured (b) = 62.2cm.

The following displacements (x) were measured from the power given on the knob of the prism:

[itex]3^{∆}[/itex] = 1.80cm
[itex]6^{∆}[/itex] = 3.51cm


Homework Equations



P = 100[itex]\frac{x}{b}[/itex]

If prisms are at 90° to each other, then resulting power will be 2P (with appropriate displacement). If prisms are at any other angle [0°,90°) then resulting power is 2Psinθ where θ is the angle between the two prism.

The Attempt at a Solution



[itex]6^{∆}[/itex] = 100[itex]\frac{x}{62.2cm}[/itex]

x = 3.73cm

This is comparable to what I recorded, however I'm unsure then why I was told to record the [itex]3^{∆}[/itex] reading and if the 2P or 2Psinθ parts were needed.
 
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Hello Pythia, and welcome to PF.
Am I right in reading ##6^{∆} ## as ##6^\circ## (six degrees) ?

It is rather difficult for an outsider to get an idea of what this is about. Could you post some more info, and perhaps a sketch of the situation ?
 

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