Finding the second displacement from the first and resultant

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SUMMARY

The discussion focuses on calculating the second displacement of a particle given its first displacement of 147 cm at an angle of 115 degrees and a resultant displacement of 188 cm at an angle of 29.6 degrees. The solution involves breaking down the displacements into their x and y components using trigonometric functions. The first displacement can be expressed as (147 cos 115°, 147 sin 115°), and the resultant displacement as (188 cos 29.6°, 188 sin 29.6°). By applying vector addition, the second displacement can be determined using the equations x1 + x2 = xtotal and y1 + y2 = ytotal.

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Homework Statement



A particle undergoes two displacements. The first has a magnitude of 147 cm and makes an angle of 115 degrees with the positive x axis. The resultant displacement has a magnitude of 188 cm and is directed at an angle of 29.6 degrees to the positive x axis.

a) Find the magnitude of the second displacement.
b) Find the direction of the second displacement (with positive measured counterclockwise from the x axis, between the limits of -180 degrees and 180 degrees).



Homework Equations



Not entirely sure.
Possibly

147{cos115,sin115}

188{cos29.6,sin29.6}



The Attempt at a Solution



I've done similar problems to this (finding the resultant displacement) but I don't know how to find the second displacement. I tried looking this problem up and couldn't find any help that led to the right answer.
 
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if you're ok with using just components, then x1+ x2 = xtotal ... gives you x2 since you know x1 and xtotal.
similarly, y1 + y2 = ytotal gives you y2 since you know y1 and ytotal.

Don't forget Pythagoras, if they want magnitudes!
 
Thanks!
 

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