Finding final kinetic energy of a system

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Homework Help Overview

The problem involves a uniform solid sphere with a spike allowing it to rotate, and a bullet impacting the sphere at a specified distance from its center. The goal is to determine the final kinetic energy of the system after the bullet embeds itself in the sphere.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of angular momentum and its relevance to the problem. There is uncertainty about the significance of the bullet's impact location and how it affects the final kinetic energy. Some participants express confusion regarding the problem's wording and the implications of the bullet's stopping point.

Discussion Status

The discussion includes various interpretations of the problem setup, with some participants seeking clarification on the impact height and its effects. There is acknowledgment of the potential for misunderstanding due to the problem's phrasing, and one participant mentions having resolved the issue independently.

Contextual Notes

Participants note that the problem's wording may be unclear and that the instructor's style can lead to confusion. There is a mention of the need for a vertical axis for the final kinetic energy to be defined, indicating a potential assumption that needs to be addressed.

stripes
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Homework Statement



A uniform solid sphere of mass M and radius R has a light, thin metal spike driven through it, so it is free to turn about this spike. So imagine a bowling ball on a stick that is free to rotate about this stick.

A bullet of mass m is fired at speed v into the ball at a distance 2R/3 from the center, and it comes to rest in the sphere. What is the final kinetic energy? Hint: angular momentum.

I recall my instructor saying it might or might not matter where the bullet ends up...but we never really concluded anything. If it does matter, let's say it ends up half way through the ball.

Homework Equations



The Attempt at a Solution



So we use angular momentum because it is conserved in this case, while linear momentum is not.

To be honest I'm not sure where to begin...I'm trying to put things together but I'm not sure where the distance 2R/3 comes into play, for example. If someone could help me out, I would really appreciate it.
 
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A likely scenario is that the bullet strikes the bowling ball horizontally at a height of 2/3 R above the horizontal center line of the ball:

attachment.php?attachmentid=63778&stc=1&d=1383948205.gif
 

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hi stripes! :smile:
stripes said:
A uniform solid sphere of mass M and radius R has a light, thin metal spike driven through it, so it is free to turn about this spike. So imagine a bowling ball on a stick that is free to rotate about this stick.

A bullet of mass m is fired at speed v into the ball at a distance 2R/3 from the center, and it comes to rest in the sphere. What is the final kinetic energy?

i think this question is totally incomprehensible :redface:

does it mean 2/3R from the stick ?

and yes of course it matters how far in the bullet stops!
 
Hey guys. I have since solved the problem. Also, I copied it verbatim as per the assignment. If you ever check my other homework questions in physics, you will find that it's not uncommon for this instructor to word them poorly, like this. I just went to see him and clarify. Thanks anyways.
 
gneill said:
A likely scenario is that the bullet strikes the bowling ball horizontally at a height of 2/3 R above the horizontal center line of the ball:

attachment.php?attachmentid=63778&stc=1&d=1383948205.gif
It will have to be a vertical axis, or there will be no 'final' KE; it will oscillate.
 
haruspex said:
It will have to be a vertical axis, or there will be no 'final' KE; it will oscillate.

Ah. True. So the "spike" is vertical and the diagram I drew is looking down on the scene from above.
 

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