Finding Force Constant of Spring: 0.296 kg & 3.3 J

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SUMMARY

The discussion centers on calculating the force constant of a spring with a mass of 0.296 kg executing simple harmonic motion, given a total energy of 3.3 J and a period of 0.18 s. The correct formula for the force constant (k) is derived from the equation T = 2π√(m/k), leading to k = m(T/2π)². A common mistake identified was using an incorrect formula that misplaces the variables, resulting in an erroneous calculation of 0.0002429276699 N/m. Proper unit analysis is emphasized as a critical step in verifying calculations.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with the formula T = 2π√(m/k)
  • Basic knowledge of energy conservation in mechanical systems
  • Ability to perform unit analysis in physics calculations
NEXT STEPS
  • Study the derivation of the formula for the period of a mass-spring system
  • Learn about energy conservation in oscillatory motion
  • Practice unit analysis techniques in physics problems
  • Explore applications of Hooke's Law in real-world scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking for examples of common calculation errors in spring dynamics.

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Homework Statement


A 0.296 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.18 s. The total energy of the system is 3.3 J. Find the force constant of the spring. Answer in units of N/m.

Homework Equations


k=m(t/2[tex]\pi[/tex])^2

The Attempt at a Solution


k=296(0.18/2[tex]\pi[/tex])^2
I get 0.0002429276699 but it is wrong. Any ideas what i did wrong?
 
Last edited:
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Your equation is wrong. The period should be T = 2pi times the square root of (m/k). I believe that your equation has (k/m) instead of (m/k). Hope that helps.
 
Note also: you should learn the trick of carrying through your units and checking them... that would have helped you find this error.
 

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