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## Homework Statement

A man lifts a 2.2 kg stone vertically with his hand at a constant velocity of 1.5 m/s. What is the force exerted by his hand on the stone?

## Homework Equations

F=ma (I would assume)

## The Attempt at a Solution

I know that (9.81 m/s^2)x(2.2 kg) = 21.582 N (the weight and the normal force) and that the force exerted by the hand must be greater than that to make the stone rise...But when there is a constant velocity, isn't the acceleration 0? How would that work with F=ma?