Finding forces on bolted platform (torques/forces)

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Homework Help Overview

The discussion revolves around analyzing forces and torques acting on a bolted platform, specifically focusing on the equilibrium conditions of the system. Participants are exploring the relationships between forces and torques in a static scenario.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the equations of motion and torque to find the forces acting on the supports. Some participants suggest examining the forces acting on each support individually, while others discuss the implications of torque balance and how it relates to the forces involved.

Discussion Status

The discussion is ongoing, with participants providing insights into the analysis of forces and torques. There is a suggestion to consider the sum of torques and the conditions for static equilibrium, indicating a productive exploration of the problem without reaching a final consensus.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available or the methods that can be used. There is an emphasis on understanding the relationships between forces and torques rather than deriving a complete solution.

austindubose
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Homework Statement


1zbt5d0.png


Homework Equations


ƩF = mA
T=rxF


The Attempt at a Solution


Using sum of forces, I found:
ƩF=mA
150lb + 50lb - F1 - F2 = 0
(calling the support on the right "1") ƩT1 = 0

But I'm a little confused on where to go from this point. Any advice?
 
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Look at each of the two supports individually. What forces act on each?
 
That would be the upward force of the board due to the torque at support 1, minus the force of the bolt holding the board to the support, correct?
 
And what can you say about the sum of the torques?
 
The sum of the torques, because there is no motion, will equal zero. Would it be correct to say the following...?
ƩT=0
0=(150lb)(2ft)-(50lb)(1ft)+(F2)(3ft)
F2=83.3lb
 

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