Finding Frictional Coefficient for Constant Speed Crate

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To find the frictional coefficient for a 1000N crate pushed at constant speed with a 300N force at a 20-degree angle below the horizontal, it's essential to accurately diagram the forces involved. The applied force has both downward and horizontal components, requiring careful resolution into x and y directions. A free body diagram is necessary to visualize all forces acting on the crate, including gravitational and normal forces. Applying Newton's laws will help in calculating the frictional force. Catching up on missed class material by consulting the instructor is also recommended for clarity.
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Homework Statement


1000N crate pushed at constant speed 300N at angle 20* below horizontal. I need to find the frictional coefficient.


Homework Equations





The Attempt at a Solution


I don't think I am even diagramming this right but here goes, Downward force is (1000N)(9.8m/s^2) Upward is (300N)(Sin20*), To the right is (300N)(cos20*) an I have no idea about to the left... I was sick in class and am pretty behind now trying to play catchup but none of the examples in the book are quite like this and I can't find very relevant help elsewhere online. Plz help=]
 
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Is there a sketch that goes along with this problem? You first have to be sure of the direction of the 300 N applied force that acts at 20 degrees below the horizontal. Is this force pushing down and to the right or up and to the right? I interpret it as acting downward and to the right, in which case it has a downward component, not an upward one. After you resolve this dilemma, you need to draw a free body diagram and show all forces acting on the crate, in both the x and y directions. There are several. Then you need to apply Newton's laws in the x and y directions. You will probably need to 'catch up' with what you missed in class by talking directly to your instructor, assuming your instructor is human and not a machine.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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