- #1

EmanuelPaz

- 3

- 0

## Homework Statement

I had a question on my test that went something like: "A 20kg box is being pulled at an angle of 37 degrees across the floor with a force of 300N at a constant velocity. What is the coefficient of friction?"

## Homework Equations

The equations I used to solve it were:

Fpx= Fp x cos(37

Fpy= Fp x sin(37

Where Fpx is the horizontal component and Fpy is the vertical component of the pulling force.

Then I solved for Fn(normal force) with the formula:

Fn= Fg(weight) - Fpy

Then for the sum of the forces in the x direction I did

Fpx - f(friction) = ma

But ma is 0 since constant velocity

so then I said Fpx = f

## The Attempt at a Solution

So from there I plugged in the value I got for Fpx which was 239.6 into f

And then I got:

f= mu(coefficient of friction) x Fn

So I got that Fn= 15.5 and I divided 239.5 by 15.5 and I got the coefficient of friction to be 15.5.