Finding Frictional Force and Time to Stop a Spinning Disk

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SUMMARY

The discussion focuses on calculating the frictional force and the time required for a spinning disk to come to rest on a flat surface. The frictional force (Ff) is determined using the formula Ff = μN, where μ is the coefficient of kinetic friction and N is the normal force, which equals mg for a horizontal surface. The time to stop (Δt) is derived from the equation Δt = R(ω - ωi) / 2μkg, where R is the radius of the disk, ω is the initial angular speed, and g is the acceleration due to gravity. The calculations assume that the normal force is equal to the gravitational force acting on the disk.

PREREQUISITES
  • Understanding of rotational dynamics, specifically torque (τ) and angular acceleration (α).
  • Familiarity with Newton's laws of motion and the concept of friction.
  • Knowledge of basic physics formulas, including Ff = μN and τ = Iα.
  • Ability to manipulate equations involving angular velocity (ω) and moment of inertia (I).
NEXT STEPS
  • Study the relationship between torque and angular acceleration in rotational motion.
  • Learn about the effects of different coefficients of friction on the stopping time of rotating objects.
  • Explore the concept of moment of inertia for various shapes and how it affects rotational dynamics.
  • Investigate real-world applications of frictional forces in mechanical systems.
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of rotating bodies and the effects of friction on motion.

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A uniform disk of radius R and mass M is spinning with angular speed ωi. It is placed on a flat horizontal surface; the coefficient of kinetic friction between the disk and surface is μk.
a) Find the frictional force on the disk.
b) How long will it take for the disk to come to rest.

I'm confused about the directions of the forces.
I know mg will be down. And there will be no forces in the x direction.

Ff = μN

Will the normal force be up, opposite and equal to the force of gravity, or will the rotation change that?

Since we don't know the direction the disk is spinning can we find the direction of ωi and α?

Can we just choose for the direction of ωi and α to be downwards from the torque of the disk?

Thanks
 
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If I have τ = Iα
Can I assume α is down?

so I can have:
ΣF = τ - f

or would it be:
ΣF = τ + mg - f - N

Iα + mg = f + N
I = ω/R
ωα/R + mg = f + N
 
another try:

τ = f x R
τ = Iα
τΔt = I(ω - ωi)
fRΔt = (1/2)MR^2(ω - ωi)
fΔt = (1/2)MR(ω - ωi)

Δt = (1/2)MR(ω - ωi) / μkFn
Δt = MR(ω - ωi) / 2μkMg
Δt = R(ω - ωi) / 2μkg

is this correct?

thanks
 

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