Finding Functions that Satisfy a Specific Relationship: A Math Olympiad Problem

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Homework Help Overview

The problem involves finding all functions \( f \) that satisfy the equation \( f(x^{2}+f(y))=y-x^{2} \) for all real numbers \( x \) and \( y \). The discussion centers on the implications of this functional equation and the reasoning behind the attempts to derive properties of \( f \).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore specific cases by substituting values for \( x \) (such as \( x=0 \), \( x>0 \), and \( x<0 \)) to derive relationships involving \( f(y) \) and \( f(0) \). There is questioning of the correctness of these substitutions and the resulting implications for the function \( f \).

Discussion Status

The discussion includes attempts to clarify reasoning and validate steps taken in the exploration of the functional equation. Some participants reference previous discussions on the topic, indicating a desire to build on or clarify existing insights rather than reach a consensus.

Contextual Notes

Participants note that the problem has been previously discussed, suggesting that there may be constraints or established interpretations that influence the current discussion. There is an emphasis on ensuring that new contributions are distinct from earlier discussions.

mtayab1994
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Homework Statement



[tex]f\left(x^{2}+f(y)\right)=y-x^{2}[/tex]


Homework Equations



Find all functions f that satisfy the relationship for every real x and y.

The Attempt at a Solution



is this correct reasoning?

for x=0: [tex]f(y)=f^{-1}(y)[/tex]

for x>0: [itex]\existsxεℝ[/itex]: [tex]x=k^{2}[/tex]

[tex]f(k^{2}+f(0))=-k^{2}+f(0)[/tex]

for x<0 [itex]\existsxεℝ[/itex]: [tex]x=-k^{2}[/tex]

[tex]f(0)=f(k^{2}+f(-k^{2}))[/tex] = [tex]f(-k^{2})-k^{2}[/tex] which entails:

[tex]f(-k^{2})=f(0)+k^{2}[/tex] =[tex]-(-k^{2})+f(0)[/tex]
 
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mtayab1994 said:

Homework Statement

[tex]f\left(x^{2}+f(y)\right)=y-x^{2}[/tex]...

for x=0: [tex]f(y)=f^{-1}(y)[/tex]
for x>0: [itex]\exists xεℝ[/itex]: [tex]x=k^{2}[/tex]
[tex]f(k^{2}+f(0))=-k^{2}+f(0)[/tex]
for x<0 [itex]\exists xεℝ[/itex]: [tex]x=-k^{2}[/tex]
[tex]f(0)=f(k^{2}+f(-k^{2}))[/tex] = [tex]f(-k^{2})-k^{2}[/tex]...
This question has been previously discussed.

http:
//www.physicsforums.com/showthread.php?t=556487


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