Finding gravity on Planet X from a string, a weight, and frequency

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Astronauts on Planet X are tasked with determining the acceleration due to gravity (g) using a 2.5 m string and a 1.3 kg mass. They observe standing waves at frequencies of 64 Hz and 80 Hz, indicating these correspond to the nth and (n+1)th modes of vibration. The linear density of the string is calculated as 0.002 kg/m, and the tension in the string is expressed as 1.3 kg multiplied by g. The fundamental frequency equation is applied, but the initial calculation yields an incorrect value of g at 81 m/s² instead of the correct 5 m/s². To solve accurately, both frequencies must be utilized to find the correct relationship for g.
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Homework Statement



Astronauts visiting Planet X have a 2.5 m-long string whose mass is 5.0 g. They tie the string to a support, stretch it horizontally over a pulley 1.8 m away, and hang a 1.3 kg mass on the free end. Then the astronauts begin to excite standing waves on the string. Their data show that standing waves exist at frequencies of 64 Hz and 80 Hz, but at no frequencies in between.

What is the value of g, the acceleration due to gravity, on Planet X?

Homework Equations



Fundamental frequency of a stretched string
f1=\frac{1}{2L}\sqrt{\frac{T_s}{\mu}}

Linear Density of a string
\mu = \frac{mass}{length}


The Attempt at a Solution



Ts = 1.3kg(g)

\mu = \frac{0.005kg}{2.5m} = 0.002

L = 1.8m

f1 = 64Hz

Place in Fundamental frequency equation and solve for g.


64Hz=\frac{1}{2(1.8m)}\sqrt{\frac{1.3*g}{0.002}

for f1 = 64Hz, I got g = 81

I tried substituting different frequencies and using a different L but I could not arrive at the correct answer which is g=5 m/s2


Can someone please teach me how to arrive at this correct answer?
 
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Here's a couple of hints.

You're given two data points in the question - that standing waves exist at the two given frequencies. So it's likely that both of them are required to arrive at the answer.

It's tempting to assume that the given data occur at the first and second natural modes of vibration, but from the wording of the question, all we can really say for sure is that they exist at the nth and (n+1)th modes - since it's given that no standing waves were found to exist at frequencies in between. Hence, we're not necessarily dealing with the fundamental frequency (n = 1) case.

Hope this helps.
 
I am still lost...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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